Seven pulleys are connected with the help of 3 light strings as shown in the figure below. Consider P 3 , P 4 , P 5 as light pulleys and pulleys P 6 and P 7 have masses m each. For this arrangement mark the correct statement(s).
A
tension in the string connecting P 1 , P 3 and P 4 is zero
B
tension in the string connecting P 1 , P 3 and P 4 is 
C
tension in all the 3 strings are same and equal to zero
D
Acceleration of 
is g downwards and that of 
is g upwards.
is g downwards and that of is g upwards.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, c)
First of all, draw FBD of 
.
Let tensions, in three strings be 
and 
, respectively.
Now draw FBD of 
and 
.
So, forces acting on 
and 
will be that of gravity and they will be in free fall. Hence, acceleration of each of them will be g downwards.
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